Optimal. Leaf size=320 \[ \frac{\left (2+\sqrt{3}\right ) \tan ^{-1}\left (\frac{\sqrt [4]{3} \left (1-\sqrt{3}\right ) \sqrt [6]{a} \left (\sqrt [3]{a}-\sqrt [3]{b} x\right )}{\sqrt{2} \sqrt{b x^3-a}}\right )}{2 \sqrt{2} 3^{3/4} a^{5/6} b^{2/3}}-\frac{\left (2+\sqrt{3}\right ) \tan ^{-1}\left (\frac{\left (1+\sqrt{3}\right ) \sqrt{b x^3-a}}{\sqrt{2} 3^{3/4} \sqrt{a}}\right )}{3 \sqrt{2} 3^{3/4} a^{5/6} b^{2/3}}-\frac{\left (2+\sqrt{3}\right ) \tanh ^{-1}\left (\frac{\sqrt [4]{3} \left (1+\sqrt{3}\right ) \sqrt [6]{a} \left (\sqrt [3]{a}-\sqrt [3]{b} x\right )}{\sqrt{2} \sqrt{b x^3-a}}\right )}{6 \sqrt{2} \sqrt [4]{3} a^{5/6} b^{2/3}}-\frac{\left (2+\sqrt{3}\right ) \tanh ^{-1}\left (\frac{\sqrt [4]{3} \sqrt [6]{a} \left (\left (1-\sqrt{3}\right ) \sqrt [3]{a}+2 \sqrt [3]{b} x\right )}{\sqrt{2} \sqrt{b x^3-a}}\right )}{3 \sqrt{2} \sqrt [4]{3} a^{5/6} b^{2/3}} \]
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Rubi [A] time = 0.189017, antiderivative size = 320, normalized size of antiderivative = 1., number of steps used = 1, number of rules used = 1, integrand size = 36, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.028 \[ \frac{\left (2+\sqrt{3}\right ) \tan ^{-1}\left (\frac{\sqrt [4]{3} \left (1-\sqrt{3}\right ) \sqrt [6]{a} \left (\sqrt [3]{a}-\sqrt [3]{b} x\right )}{\sqrt{2} \sqrt{b x^3-a}}\right )}{2 \sqrt{2} 3^{3/4} a^{5/6} b^{2/3}}-\frac{\left (2+\sqrt{3}\right ) \tan ^{-1}\left (\frac{\left (1+\sqrt{3}\right ) \sqrt{b x^3-a}}{\sqrt{2} 3^{3/4} \sqrt{a}}\right )}{3 \sqrt{2} 3^{3/4} a^{5/6} b^{2/3}}-\frac{\left (2+\sqrt{3}\right ) \tanh ^{-1}\left (\frac{\sqrt [4]{3} \left (1+\sqrt{3}\right ) \sqrt [6]{a} \left (\sqrt [3]{a}-\sqrt [3]{b} x\right )}{\sqrt{2} \sqrt{b x^3-a}}\right )}{6 \sqrt{2} \sqrt [4]{3} a^{5/6} b^{2/3}}-\frac{\left (2+\sqrt{3}\right ) \tanh ^{-1}\left (\frac{\sqrt [4]{3} \sqrt [6]{a} \left (\left (1-\sqrt{3}\right ) \sqrt [3]{a}+2 \sqrt [3]{b} x\right )}{\sqrt{2} \sqrt{b x^3-a}}\right )}{3 \sqrt{2} \sqrt [4]{3} a^{5/6} b^{2/3}} \]
Antiderivative was successfully verified.
[In] Int[x/((2*(5 - 3*Sqrt[3])*a - b*x^3)*Sqrt[-a + b*x^3]),x]
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Rubi in Sympy [A] time = 35.9728, size = 68, normalized size = 0.21 \[ - \frac{x^{2} \sqrt{- a + b x^{3}} \operatorname{appellf_{1}}{\left (\frac{2}{3},\frac{1}{2},1,\frac{5}{3},\frac{b x^{3}}{a},\frac{b x^{3}}{2 a \left (- 3 \sqrt{3} + 5\right )} \right )}}{4 a^{2} \sqrt{1 - \frac{b x^{3}}{a}} \left (- 3 \sqrt{3} + 5\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(x/(-b*x**3+2*a*(5-3*3**(1/2)))/(b*x**3-a)**(1/2),x)
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Mathematica [C] time = 0.684906, size = 243, normalized size = 0.76 \[ -\frac{10 \left (26-15 \sqrt{3}\right ) a x^2 F_1\left (\frac{2}{3};\frac{1}{2},1;\frac{5}{3};\frac{b x^3}{a},\frac{b x^3}{10 a-6 \sqrt{3} a}\right )}{\left (3 \sqrt{3}-5\right ) \sqrt{b x^3-a} \left (2 \left (3 \sqrt{3}-5\right ) a+b x^3\right ) \left (10 \left (3 \sqrt{3}-5\right ) a F_1\left (\frac{2}{3};\frac{1}{2},1;\frac{5}{3};\frac{b x^3}{a},\frac{b x^3}{10 a-6 \sqrt{3} a}\right )-3 b x^3 \left (F_1\left (\frac{5}{3};\frac{1}{2},2;\frac{8}{3};\frac{b x^3}{a},\frac{b x^3}{10 a-6 \sqrt{3} a}\right )+\left (5-3 \sqrt{3}\right ) F_1\left (\frac{5}{3};\frac{3}{2},1;\frac{8}{3};\frac{b x^3}{a},\frac{b x^3}{10 a-6 \sqrt{3} a}\right )\right )\right )} \]
Warning: Unable to verify antiderivative.
[In] Integrate[x/((2*(5 - 3*Sqrt[3])*a - b*x^3)*Sqrt[-a + b*x^3]),x]
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Maple [C] time = 0.097, size = 510, normalized size = 1.6 \[{\frac{-{\frac{i}{27}}\sqrt{2}}{a{b}^{3}}\sum _{{\it \_alpha}={\it RootOf} \left ( b{{\it \_Z}}^{3}+6\,a\sqrt{3}-10\,a \right ) }{\frac{1}{{\it \_alpha}}\sqrt [3]{a{b}^{2}}\sqrt{{-{\frac{i}{2}}b \left ( 2\,x+{\frac{1}{b} \left ( i\sqrt{3}\sqrt [3]{a{b}^{2}}+\sqrt [3]{a{b}^{2}} \right ) } \right ){\frac{1}{\sqrt [3]{a{b}^{2}}}}}}\sqrt{{b \left ( x-{\frac{1}{b}\sqrt [3]{a{b}^{2}}} \right ) \left ( -3\,\sqrt [3]{a{b}^{2}}-i\sqrt{3}\sqrt [3]{a{b}^{2}} \right ) ^{-1}}}\sqrt{{{\frac{i}{2}}b \left ( 2\,x+{\frac{1}{b} \left ( -i\sqrt{3}\sqrt [3]{a{b}^{2}}+\sqrt [3]{a{b}^{2}} \right ) } \right ){\frac{1}{\sqrt [3]{a{b}^{2}}}}}} \left ( -3\,i\sqrt [3]{a{b}^{2}}{\it \_alpha}\,\sqrt{3}b+4\,{b}^{2}{{\it \_alpha}}^{2}\sqrt{3}+3\,i \left ( a{b}^{2} \right ) ^{{\frac{2}{3}}}\sqrt{3}-2\,\sqrt [3]{a{b}^{2}}{\it \_alpha}\,\sqrt{3}b-6\,i\sqrt [3]{a{b}^{2}}{\it \_alpha}\,b+6\,{b}^{2}{{\it \_alpha}}^{2}-2\, \left ( a{b}^{2} \right ) ^{2/3}\sqrt{3}+6\,i \left ( a{b}^{2} \right ) ^{{\frac{2}{3}}}-3\,\sqrt [3]{a{b}^{2}}{\it \_alpha}\,b-3\, \left ( a{b}^{2} \right ) ^{2/3} \right ){\it EllipticPi} \left ({\frac{\sqrt{3}}{3}\sqrt{{-i\sqrt{3}b \left ( x+{\frac{1}{2\,b}\sqrt [3]{a{b}^{2}}}+{\frac{{\frac{i}{2}}\sqrt{3}}{b}\sqrt [3]{a{b}^{2}}} \right ){\frac{1}{\sqrt [3]{a{b}^{2}}}}}}},{\frac{1}{6\,ab} \left ( -2\,i\sqrt [3]{a{b}^{2}}{{\it \_alpha}}^{2}\sqrt{3}b+i \left ( a{b}^{2} \right ) ^{{\frac{2}{3}}}{\it \_alpha}\,\sqrt{3}-4\,i\sqrt [3]{a{b}^{2}}{{\it \_alpha}}^{2}b-2\, \left ( a{b}^{2} \right ) ^{2/3}{\it \_alpha}\,\sqrt{3}+2\,i \left ( a{b}^{2} \right ) ^{{\frac{2}{3}}}{\it \_alpha}+i\sqrt{3}ab-3\, \left ( a{b}^{2} \right ) ^{2/3}{\it \_alpha}+2\,\sqrt{3}ab+2\,iab+3\,ab \right ) },\sqrt{{\frac{-i\sqrt{3}}{b}\sqrt [3]{a{b}^{2}} \left ( -{\frac{3}{2\,b}\sqrt [3]{a{b}^{2}}}-{\frac{{\frac{i}{2}}\sqrt{3}}{b}\sqrt [3]{a{b}^{2}}} \right ) ^{-1}}} \right ){\frac{1}{\sqrt{b{x}^{3}-a}}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(x/(-b*x^3+2*a*(5-3*3^(1/2)))/(b*x^3-a)^(1/2),x)
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ -\int \frac{x}{{\left (b x^{3} + 2 \, a{\left (3 \, \sqrt{3} - 5\right )}\right )} \sqrt{b x^{3} - a}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(-x/((b*x^3 + 2*a*(3*sqrt(3) - 5))*sqrt(b*x^3 - a)),x, algorithm="maxima")
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(-x/((b*x^3 + 2*a*(3*sqrt(3) - 5))*sqrt(b*x^3 - a)),x, algorithm="fricas")
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x/(-b*x**3+2*a*(5-3*3**(1/2)))/(b*x**3-a)**(1/2),x)
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GIAC/XCAS [A] time = 0.575117, size = 4, normalized size = 0.01 \[ \mathit{sage}_{0} x \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(-x/((b*x^3 + 2*a*(3*sqrt(3) - 5))*sqrt(b*x^3 - a)),x, algorithm="giac")
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